The SBI PO Prelims exam 2021 has been scheduled to be held on November 20, 21 & 27, 2021. In these last few days, we hope you are practicing more and more sample questions every day. In this article, we have put together some tricks and tips that you can use as you prepare for your exam. We have also curated a list of solved and unsolved questions from a number of topics that you can take help from to understand the kind of questions you may expect.
Contents
Important Points to Remember
For the SBI PO Prelims exam, out of 35 questions, 23-24 questions will be asked from the below mentioned first 4 topics. The remaining questions will be from Arithmetic Word Problems.
Topic | Level of Assessment | No. of Question |
Data Interpretation | Easy to Moderate | 10-15 |
Quadratic Equations | Easy | 5 |
Number Series | Easy | 5 |
Simplification/Approximation | Easy | 5 |
Arithmetic Word Problems (Time & Work, Percentage and such) | Easy to Moderate | 11-12 |
Some calculation tricks that you must know if you are appearing for the SBI PO exam are provided below. These tricks will definitely help you in increasing your speed and you will be able to attempt more questions in the exam.
Trick #1
Square of the numbers ending with 5.
We can find the Square of any number whose last digit is 5.
Just write 25 in the end & multiply the digit ahead of 5 to its next place & put the product before 25. Simply you will get the final answer
It means, n5^{2} = n(n+1)/25
So, 45^{2} = 4×5/25 = 2025
55^{2} = 5×6/25 = 3025
65^{2} = 6×7/25 = 4225
105^{2} = 10×11/25 = 11025
Trick #2
Square of numbers near to 50.
If the number is more than 50, then
(50+n)^{2} = (25+n)/n^{2}
In the end n^{2} must have only 2 digits. If it has only 1 digit like 3^{2} =9, we will write it as 09.
If it has 3 digits like 12^{2} = 144 then write 44 in the end only & carry 1 in (25+n)
It means 53^{2} = (50+3)^{2} = 25+3/3^{2} = 2809
52^{2} = (50+2)^{2} = 25+2/2^{2} = 2704
56^{2} = (50+6)^{2} = 25+6/6^{2} = 3136
62^{2} = (50+12)^{2} = 25+12/12^{2} = 37/144 = 37+1/44 = 3844
64^{2} = (50+14)^{2} = 25+14/14^{2} = 39/196 = 39+1/96 = 4096
If the number is less than 50, then
(50-n)^{2} = (25-n)/n^{2}
In the end n^{2} must have only 2 digits. If it has only 1 digit like 3^{2} =9, we will write it as 09.
If it has 3 digits like 12^{2} = 144 then write 44 in the end only & carry 1 in (25+n)
It means 47^{2} = (50-3)^{2} = 25-3/3^{2} = 2209
48^{2} = (50-2)^{2} = 25-2/2^{2} = 2304
44^{2} = (50-6)^{2} = 25-6/6^{2} = 1936
38^{2} = (50-12)^{2} = 25-12/12^{2} = 13/144 = 13+1/44 = 1444
36^{2} = (50-14)^{2} = 25-14/14^{2} = 11/196 = 11+1/96 = 1296
Trick #3
Square of numbers near to 100.
If the number is more than 100, then
(100+n)^{2} = (100+n+n)/n^{2}
In the end n^{2} must have only 2 digits. If it has only 1 digit like 3^{2} =9, we will write it as 09.
If it has 3 digits like 12^{2} = 144 then write 44 in the end only & carry 1 in (100+n+n)
It means 103^{2} = (100+3)^{2} =100+3+3/3^{2} = 10609
102^{2} = (100+2)^{2} =100+2+2/2^{2} = 10404
106^{2} = (100+6)^{2} =100+6+6/6^{2} = 11236
112^{2} = (100+12)^{2} = 100+12+12/12^{2} = 124/144 = 124+1/44 = 12544
114^{2} = (100+14)^{2} = 100+14+14/14^{2} = 128/196 = 128+1/96 = 12996
If the number is less than 100, then
(100-n)^{2} = (100-n-n)/n^{2}
In the end n^{2} must have only 2 digits. If it has only 1 digit like 3^{2} =9, we will write it as 09.
If it has 3 digits like 12^{2} = 144 then write 44 in the end only & carry 1 in (100-n-n)
It means 97^{2} = (100-3)^{2} =100-3-3/3^{2} = 9409
98^{2} = (100-2)^{2} =100-2-2/2^{2} =9604
94^{2} = (100-6)^{2} =100-6-6/6^{2} = 8836
88^{2} = (100-12)^{2} = 100-12-12/12^{2} = 76/144 = 76+1/44 = 7744
86^{2} = (100-14)^{2} = 100-14-14/14^{2} = 72/196 = 72+1/96 = 7396
Some Other Tips
- Memorize squares upto 50 (minimum 30)
- Memorize cubes upto 20
- Memorize multiplication tables upto 20
- Percentage to fraction conversion and vice versa
- Practice DI/Simplification/Approximation/Number Series and Quadratic equations problems every day.
How to Approach Quantitative Aptitude section.
- Try to solve the easy problems first and then gradually move to the Moderate/Difficult ones.
- In continuation with the last point, attempt questions from Approximation/ Simplification, Quadratic Equations and Number Series first as these take comparatively lesser time.
- Don’t spend undue time on analyzing the pattern of the number series, just give it a quick read and if you get the pattern go ahead, otherwise skip and move to next.
- Attempt DI only if you have practiced well. If you haven’t practiced enough, try to solve the rest of the questions first and then move into this section as it can be quite time-consuming.
- Don’t spend too much time on one question. If you don’t know the answer, move on to the next.
- Accuracy is key. While it is important to answer as many questions as you can, it is imperative that you answer these questions correctly to score marks.
Solved Sample Questions
In this section, we have compiled some solved examples for your perusal. Take a look at them below.
- What will come in place of the question mark (?) in the following series?
8, 17, 36, 75, ?, 313
Solution:
8 × 2 + 1 = 17
17 × 2 + 2 = 36
36 × 2 + 3 = 75
75 × 2 + 4 = 154
154 × 2 + 5 = 313
Answer: 154
- ‘n’ men working 18 hours a day can complete a work in 24 days while (5n – 4) men working 12 hours a day can complete the same work in 9 days. In how many days can (n + 4) men working 6 hours a day complete the same work?
Solution:
According to the question,
(n × 18 × 24) = {(5n – 4) × 12 × 9}
Or, 4n = 5n – 4
Or, n = 4
Let the number of days taken by (n + 4) = 8 men be ‘x’ days
Therefore,
(8 × 18 × 24) = (8 × 6 × x)
Therefore, x = 72 days
Answer: 72 days
- A man invested Rs. 2x and Rs. 4x at 10% simple interest and at 5% compound interest (compounded annually) for two years respectively. Difference between simple interest and compound interest received after two years is Rs.680. Find the value of x.
Solution:
According to the question,
=> [4x (1.05)^{2} – 4x] – (2x × 10 × 2)/100 = 680
=> [4.41x – 4x] – (4x/10) = 680
=> 0.1x = 6800
=> x = Rs. 68000
Answer: Rs 68,000
- Average of present ages of A and B is 30 years. Ratio of age of A to age of B, after 10 years will be 7:9, respectively. What will be the ratio of their ages 5 years ago?
Solution:
Let, present age of A is ‘x’ years
Present age of B = 30 × 2 – x = ‘60 – x’ years
According to question;
(x + 10)/(60 – x + 10) = 7/9
Or, 9x + 90 = 490 – 7x
Or, 16x = 400
Or, x = 25
Desired ratio = (25 – 5) :(60 – 25 – 5) = 20:30 = 2:3
Answer: 2:3
Sample Question for Practice
We have provided a list of questions from a variety of topics for your practice. Test yourselves on these topics and let us know how you fared.
Q1. Answer the questions based on the information given below.
The cost of per click per person for a website page is different for different days. The table given below shows the total amount of money collected from a website on different days of a week and average price of a per click on the respective days. The table also shows the ratio of number of males to female visitors to the website on different days of a week.
Days | Total amount collected | Average cost of per click per person | Ratio of number of male visitors to female visitors |
Monday | 7800 | 15 | 9:4 |
Tuesday | 8640 | 20 | 7:5 |
Wednesday | 14000 | 25 | 3:2 |
Thursday | 8100 | 18 | 5:4 |
Friday | 21600 | 30 | 8:7 |
Qi. What is the average number of visitors to the website on Monday, Wednesday and Friday together?
(a) 600
(b) 650
(c) 750
(d) 850
(e) none of these
Qii. Total number of visitors on Saturday is 40% more than the same on Thursday while the number of male visitors on Saturday is 48% more than the same on Thursday. Find the number of female visitors to the website on Saturday.
(a) 260
(b) 200
(c) 250
(d) 230
(e) none of these
Qiii. 45%, 60% and 62.5% of the females who visited the website on Monday, Tuesday and Wednesday respectively. Find the number of female visitors who visited the website in these three days.
(a) 360
(b) 320
(c) 200
(d) 330
(e) none of these
Q2. A, B and C started a business by investing Rs. a, Rs. a + 4000 and Rs. a + 9000 respectively. After 6 months, A withdraws Rs. 1000. And after another 2 months, B invested Rs. 2500 more. Find the value of a, if the share of A, B and C at the end of the year is in the ratio of 33: 65: 90?
(a) 12000
(b) 1500
(c) 1800
(d) 1650
(e) 1850
Q3. In three cities A, B and C, the total number of cars (electric and non-electric) are in the ratio 9:8:3. In A, 80% of the cars are non-electric, in B, 30% of the people are electric. If 90% of cars in city C are non-electric. Find the percentage of non-electric cars in these three cities.
(a) 66.5%
(b) 77.5%
(c) 55.5%
(d) 60.5%
(e) 65.75%
Q4. What will come in place of the question mark (?) in the following series?
12, 31, 48, ?, 72, 79
(a) 62
(b) 65
(c) 61
(d) 70
(e) 60
Q5. A invested a sum at a certain rate of interest on simple interest and he got 90% more amount after 4 years. If he invests Rs. 7200 at the same rate of interest on SI, then find the total interest he would get after 5 years?
(a) 12000
(b) 15000
(c) 8100
(d) 6650
(e) 8850
Q6. The speed of current is 12 km/h. What will be the respective downstream speed and upstream speed of a boy rowing a boat, if one fifth of the distance covered going downstream in a certain time is equal to the distance covered going upstream in the same time?
(a) 30 km/h, 8 km/hr
(b) 30 km/h, 6 km/hr
(c) 32 km/h, 6 km/hr
(d) 30 km/h, 9 km/hr
(e) 35 km/h, 6 km/hr
Q7. What will come in the place of the question mark (?) in the given expression?
21% of 4200 – 42% of 2100 + 12 × 5 = ?% of 240
(a) 20
(b) 25
(c) 26
(d) 33
(e) 28
Want the answer key? Comment your answers below and we will get back to you with the correct answers.
We hope these sample questions help you in your preparation. If you want to practice more questions, it would be a good idea to take an SBI PO Prelims free mock test with ixamBee. In this way, you will be able to evaluate the kind of questions asked in all subjects and not only Quantitative Aptitude.
There are 5 free mock tests available at ixamBee! Take one now!
Also take a look at SBI PO Prelims Previous Year Papers as well.
If you need any other clarification or any sort of assistance, please feel free to reach out to us.
All the best!
Also read
SBI PO 2021 Admit Card [Out]: Direct Link for Download
SBI PO 2021 Syllabus: Find the Complete Syllabus Here