Question
I. x2 + 24x + 143 = 0 II.
y2 + 12y + 35 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and determine the relationship between them and give answer:Solution
I. x2Â + 24x + 143 = 0 Pairs are 11 and 13 Values after changing sign = -11, -13 II. y2+ 12y + 35 = 0 Pairs are 7 and 5 Values after changing sign = -7, -5 Hence, x < y
More Quadratic equation Questions
I. 3p2Â - 11p + 10 = 0
II. 42q2Â + q -1 = 0
I). p2 + 22p + 72 = 0,
II). q2 - 24q + 128 = 0
Find the roots of the equation 6p² – 5p – 6 = 0.
I. y² + y – 56 = 0
II. 2x² + 11 x – 40 = 0
 If x satisfies x² – 14x + 40 = 0, find x.
I. 2y² - 35y + 132 = 0
II. 2x² - 31x + 110 = 0
I. 35x² - 46x – 16 = 0
II. 35y² - 116y + 96 = 0
I. 20x² - 93x + 108 = 0
II.72y² - 47y - 144 = 0
I. x3 = 1728
II. y2 – 15y + 56 = 0
I. x2 + x – 42 = 0
II. y2 + 6y – 27 = 0
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