Question
Equation 1: x² - 45x + 500 = 0 Equation 2: y² -
60y + 600 = 0Solution
x² - 45x + 500 = 0 Factorizing: (x - 25)(x - 20) = 0 So, x = 25 or x = 20. From Equation 2: y² - 60y + 600 = 0 Factorizing: (y - 30)(y - 20) = 0 So, y = 30 or y = 20. Comparing x and y: x = 25, y = 30, x < y x = 25, y = 20, x > y x = 20, y = 30, x < y x = 20, y = 20, x = y Correct option: E) x = y or no relation
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 19x² - 92x + 73 = 0
Equation 2: 17y² - 76y + 59 = 0
I). p2 - 26p + 165 = 0
II). q2 + 8q - 153 = 0
I. 6x2 - 41x+13=0
II. 2y2 - 19y+42=0
I. 81x - 117√x + 40 = 0
II. 81y - 225√y + 136 = 0
I. 20y² - 13y + 2 = 0
II. 6x² - 25x + 14 = 0
If the roots of the quadratic equation 6m² + 7m + 8 = 0 are α and β, then what is the value of [(1/α) + (1/β)]?
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. 2x2 - 9 x + 9 = 0
II. 2y2 - 7 y + 3 = 0
I. x² - 19x + 84 = 0
II. y² - 25y + 156 = 0
I. p² - 10p +21 = 0
II. q² + q -12 = 0
