Question
‘A’ is 100% more efficient than ‘C’, while
‘B’ is 200% more efficient than ‘A’. Together, they complete a task in 15 days. After ‘A’ and ‘C’ work for 9 days, they stop. How long will ‘B’ take to finish the remaining work?Solution
Let efficiency of ‘C’ = x units/day
Efficiency of ‘A’ = 2x units/day
Efficiency of ‘B’ = 3 × 2x = 6x units/day Total work = (2x + 6x + x) × 15
= 9x × 15 = 135x units Work done by ‘A’ and ‘C’ in 9 days = (2x + x) × 9 = 3x × 9 = 27x units Remaining work = 135x – 27x = 108x units Time required by ‘B’ = 108x / 6x = 18 days
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