Question
‘A’ is 100% more efficient than ‘C’, while
‘B’ is 200% more efficient than ‘A’. Together, they complete a task in 15 days. After ‘A’ and ‘C’ work for 9 days, they stop. How long will ‘B’ take to finish the remaining work?Solution
Let efficiency of ‘C’ = x units/day
Efficiency of ‘A’ = 2x units/day
Efficiency of ‘B’ = 3 × 2x = 6x units/day Total work = (2x + 6x + x) × 15
= 9x × 15 = 135x units Work done by ‘A’ and ‘C’ in 9 days = (2x + x) × 9 = 3x × 9 = 27x units Remaining work = 135x – 27x = 108x units Time required by ‘B’ = 108x / 6x = 18 days
1299.99 ÷ 20.21 = ? + 325.985 - (180 ÷ 6 × 24.03)
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(599.90 ÷ 12.02) + (179.98 ÷ 6.00) = ?% of 200.0 - 20.3
√92.10 + √256.30 + 60.78% of (420.90 + 19.36% of 140.25) = ?
- √143.88 X 31.87 + √323.99 X 15.99 - 31.99 X √195 = ?
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