Question
Vikas does 65% of a job in 39 days, while Suman does 40% in
40 days. Vikas worked for 18 days and left. Calculate how many days Suman would need to wrap up the remaining task.Solution
ATQ,
Vikas’ full-time = 39 / 0.65 = 60 days
Suman’s full-time = 40 / 0.40 = 100 days
Total work = LCM(60, 100) = 300 units
Vikas’ efficiency = 300 / 60 = 5 units/day
Suman’s efficiency = 300 / 100 = 3 units/day
Work done by Vikas = 18 × 5 = 90 units
Remaining work = 300 - 90 = 210 units
Time by Suman = 210 / 3 = 70 days
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 37x² - 172x + 135 = 0
Equation 2: 29y² - 132y + ...
I. p2 - 19p + 88 = 0Â Â
II. q2 - 48q + 576 = 0
For what real value(s) of k does the quadratic equation - x² − (k + 3)x + 2k = 0, have equal real roots?
I. x2 – 12x + 32 = 0
II. y2 + y - 20 = 0
I. 195x² - 46x - 21 = 0
II. 209y² + 13y - 12 = 0
I. x² - (16)2 = 0
II. 2y - 14 = 0
Solve for x: |2x − 5| + |x + 1| ≤ 10.
I. 9x2 + 45x + 26 = 0
II. 7y2 – 59y − 36 = 0
Roots of the quadratic equation 2x2 + x – 528 = 0 is
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