Question
Solve for x: |2x β 5| + |x + 1| β€
10.Solution
ATQ,
Critical points at x = 2.5 and x = β1. Case 1: x β₯ 2.5 β (2x β 5) + (x + 1) β€ 10 β 3x β 4 β€ 10 β x β€ 14/3. So 2.5 β€ x β€ 14/3. Case 2: β1 β€ x β€ 2.5 β (5 β 2x) + (x + 1) β€ 10 β 6 β x β€ 10 β βx β€ 4 β x β₯ β4. In this band, itβs all valid: β1 β€ x β€ 2.5. Case 3: x β€ β1 β (5 β 2x) + (βx β 1) β€ 10 β 4 β 3x β€ 10 β β3x β€ 6 β x β₯ β2. So in this band: β2 β€ x β€ β1. Combine: β2 β€ x β€ 14/3. Answer: x β [β2, 14/3].
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