Practice Quadratic equation Questions and Answers
- I. β(17x) + β51 = 0Β Β Β II. β(4y) + 3 = 0
- I. x2 β 36 = 0 II. y2 - 7y + 6 = 0
- I. x + 1 = 3β 9261 II. y + 1 = β 324
- I. (y β 5)2 β 9 = 0 II. x2 β 3x + 2 = 0
- I. 6x2 β 7x - 20 = 0 II. 3y2Β - y - 14 = 0
- Equation 1: 2x2Β - 21x + 54 = 0 Equation 2: 4y2Β - 23y + 15 = 0 Difference between the roots of equation 1 is approximately how much% more or less than the...
- What is the speed of the stream if a ship takes 15 hours to travel 240 km in calm waters, given that the ratio of its speed against the current to its spee...
- 1.3wx = 40 β wy 2. b2 = 2b + p 3. d2 + d = q Now, observe the given conditions: One root of equation 1 is -8. There exists a common root between equation...
- Let 's' represent the sum of the highest root of equations I and III, and 'r' denote the product of the lowest root of equation I and the highest root of e...
- Solve both equations I & II and form a new equation III in variable βrβ (reduce to lowest possible factor) using roots of equation I and II as per ins...
- I. 2p2 + 25p β 13 = 0 II. 2q2 β 19q = 2q + 23
- I. 6p2 β 7p = 5p β 7p2 + 25 II. 11q2 β 63q + 90 = 0
- I. 27(p + 2) = 2p(24 β p) II. 2q2 β 25q + 78 = 0
- I. 25p + 2(2p2 β 1) = 8(p + 5) II. 8q2 + 35q β 78 = 0
- I. 14p2 β 135p + 81 = 0 II. 7q2 β 65q + 18 = 0
- LCM of 'x' and 'y' is 30 and their HCF is 1 such that {10 > x > y > 1}. I. 2pΒ²- (x + y) p + 3y = 0 II. 2qΒ² + (9x + 2) = (3x + y) q
- If x^2 - 7x + k = 0 has roots that are equal, what is the value of k?
- What will be the product of smaller roots of both equations.Β
- I). 5p2 Β - p - 4 = 0 II). q2 - 12q + 27 = 0
- I). p2 + 8p + 15 = 0 II). q2 + 9q + 20 = 0
- I). 4p + 3q = 25 II). 5p + 2q = 26Β
- I). p2 + 17p - 234 = 0 II). q2 - 21q + 108 = 0
- I). p2 = 81 II). q2 - 9q + 14 = 0
- I:Β x2Β - 33x + 242 = 0 II:Β y2Β - 4y - 77 = 0
- I: x2Β + 31x + 228 = 0 II: y2Β + 3y β 108 = 0
- I: 2xΒ² - 8x + 6 = 0 II: 3yΒ² - 12y + 9 = 0
- I: xΒ² - 10x + 21 = 0Β Β II: 4yΒ² - 16y + 15 = 0
- I: 3xΒ² - 18x + 24 = 0 II: 5yΒ² + 10y - 15 = 0
- Solve the quadratic equations and determine the relation between x and y: Equation 1: xΒ² - 34x + 285 = 0 Equation 2: yΒ² - 26y + 165 = 0
- Solve the quadratic equations and determine the relation between x and y: Equation 1: xΒ² - 24x + 135 = 0 Equation 2: yΒ² - 26y + 153 = 0
- Solve the quadratic equations and determine the relation between x and y: Equation 1: xΒ² - 40x + 300 = 0 Equation 2: yΒ² - 30y + 216 = 0
- Solve the quadratic equations and determine the relation between x and y: Equation 1: xΒ² - 36x + 288 = 0 Equation 2: yΒ² - 36y + 320 = 0
- Solve the quadratic equations and determine the relation between x and y: Equation 1: xΒ² - 40x + 375 = 0 Equation 2: yΒ² - 36y + 324 = 0
- Solve the quadratic equations and determine the relation between x and y: Equation 1: xΒ² - 42x + 392 = 0 Equation 2: yΒ² - 46y + 480 = 0
- Solve the quadratic equations and determine the relation between x and y: Equation 1: xΒ² - 32x + 207 = 0 Equation 2: yΒ² - 51y + 648 = 0
- Solve the quadratic equations and determine the relation between x and y: Equation 1: xΒ² - 50x + 600 = 0 Equation 2: yΒ² - 51y + 630 = 0
- Solve the quadratic equations and determine the relation between x and y: Equation 1: xΒ² - 54x + 704 = 0 Equation 2: yΒ² - 44y + 448 = 0
- Solve the quadratic equations and determine the relation between x and y: Equation 1: xΒ² - 22x + 120 = 0 Equation 2: yΒ² - 25y + 144 = 0
- Solve the quadratic equations and determine the relation between x and y: Equation 1: xΒ² - 24x + 143 = 0 Equation 2: yΒ² - 26y + 165 = 0
- Solve the quadratic equations and determine the relation between x and y: Equation 1: xΒ² - 21x + 110 = 0 Equation 2: yΒ² - 23y + 132 = 0
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