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      Question

      Solve the quadratic equations and determine the relation

      between x and y: Equation 1: x² - 42x + 392 = 0 Equation 2: y² - 46y + 480 = 0
      A x > y Correct Answer Incorrect Answer
      B x ≥ y Correct Answer Incorrect Answer
      C x < y Correct Answer Incorrect Answer
      D x ≤ y Correct Answer Incorrect Answer
      E x = y or no relation Correct Answer Incorrect Answer

      Solution

      From Equation 1: x² - 42x + 392 = 0 Factorizing: (x - 14)(x - 28) = 0 So, x = 14 or x = 28. From Equation 2: y² - 46y + 480 = 0 Factorizing: (y - 16)(y - 30) = 0 So, y = 16 or y = 30. Comparing x and y: x = 14, y = 16, x < y x = 14, y = 30, x < y x = 28, y = 16, x > y x = 28, y = 30, x < y

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