Question
I. x2 β 19x + 88 = 0 II. (y +
4)2 = 121 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer:Solution
I. x2Β β 19x + 88 = 0 => x2Β β 11x - 8x + 88 = 0 => x(x β 11) - 8(x β 11) = 0 => (x β 11) (x - 8) = 0 => x = 11, 8 II. (y + 4)2Β = 121 => y2Β + 16 + 8y = 121 => y2Β + 8y β 105 = 0 => y2Β + 15y - 7y - 105 = 0 => y(y + 15) - 7(y + 15) = 0 => (y + 15) (y - 7) = 0 => y = -15, 7 Hence, x > y.
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