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    Question

    I. x2 тАУ 19x + 88 = 0 II. (y +

    4)2 = 121 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer:
    A if x > y Correct Answer Incorrect Answer
    B if x тЙе y Correct Answer Incorrect Answer
    C if x < y Correct Answer Incorrect Answer
    D if x тЙд y Correct Answer Incorrect Answer
    E if x = y or the relationship cannot be established Correct Answer Incorrect Answer

    Solution

    I. x2┬атАУ 19x + 88 = 0 => x2┬атАУ 11x - 8x + 88 = 0 => x(x тАУ 11) - 8(x тАУ 11) = 0 => (x тАУ 11) (x - 8) = 0 => x = 11, 8 II. (y + 4)2┬а= 121 => y2┬а+ 16 + 8y = 121 => y2┬а+ 8y тАУ 105 = 0 => y2┬а+ 15y - 7y - 105 = 0 => y(y + 15) - 7(y + 15) = 0 => (y + 15) (y - 7) = 0 => y = -15, 7 Hence, x > y.

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