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      Question

      I. x2 + x – 42 = 0 II. y2

      + 6y – 27 = 0 In each of the following questions, there are two equations. You have to solve both equations and mark the correct answer.
      A if x > y Correct Answer Incorrect Answer
      B if x ≥ y Correct Answer Incorrect Answer
      C if x < y Correct Answer Incorrect Answer
      D if x = y or relationship cannot be established. Correct Answer Incorrect Answer
      E if x > y Correct Answer Incorrect Answer

      Solution

      I. x2 + x – 42 = 0 => x2 + 7x – 6x – 42 = 0 => x(x + 7) – 6(x + 7) = 0 => (x + 7) (x -6) = 0 => x = -7, 6 II. y2 + 6y – 27 = 0 => y2 + 9y – 3y – 27 = 0 => y(y + 9) – 3(y + 9) = 0 => (y + 9) (y – 3) = 0 => y = -9, 3 Hence, the relationship cannot be established between x and y.

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