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    Question

    One type of liquid contains 15% of benzene, the other

    contains 20% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture.
    A 27% Correct Answer Incorrect Answer
    B 32% Correct Answer Incorrect Answer
    C 22% Correct Answer Incorrect Answer
    D 17% Correct Answer Incorrect Answer
    E 24% Correct Answer Incorrect Answer

    Solution

    Let the percentage of benzene in the new mixture = x (20 - x)/(x - 15) = 6/4 = 3/2 5x = 85 x = 17 So, required percentage of benzene = 17%

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