Question
One type of liquid contains 15% of benzene, the other
contains 20% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture.Solution
Let the percentage of benzene in the new mixture = x (20 - x)/(x - 15) = 6/4 = 3/2 5x = 85 x = 17 So, required percentage of benzene = 17%
More Alligation Questions
- What will come in the place of question mark (?) in the given expression?
1231 + 1312 + 2113 – 3211 = ? Simplify the following expression:
84 - [21 - {14 - (25 - 16 + 8) }] ÷ 3 X 6
?% of 24% of 1200 + 12 × 11 = 204
154 × 7 + 480 × 5 =?% of 6956
- What will come in place of (?) in the given expression.
√324 + √121 – √49 = ? What will come in the place of question mark (?) in the given expression?
[{(24) 2 ÷ (6) 2 } ÷ 8]4 = ? ÷ 5
[(36 × 15 ÷ 96 + 19 ÷ 8) × 38] = ?% of 608
115 ÷ 23 + 12 × 6 = ? + 16 - 35
6 × 5.5 + 4.5 × 20 - 102 = ?