Question
‘D’ and ‘E’ can complete a project in 40 days,
while ‘E’ and ‘F’ can complete it in 60 days. ‘D’ and ‘E’ worked together on it for 30 days and then ‘F’ alone completed the remaining work in 20 days. If ‘D’, ‘E’, and ‘F’ started the project and worked together till its completion for which they received Rs. 1800 as total wage, then the share of ‘D’ out of the total wage will be:Solution
Let the total amount of work = 240 units (LCM of 40 and 60) Work done by ‘D’ and ‘E’ together in one day = 240 / 40 = 6 units Work done by ‘E’ and ‘F’ together in one day = 240 / 60 = 4 units Work done by ‘D’ and ‘E’ together in 30 days = 30 × 6 = 180 units Remaining work = 240 - 180 = 60 units Efficiency of ‘F’ = 60 / 20 = 3 units per day Efficiency of ‘E’ = 4 - 3 = 1 unit per day Efficiency of ‘D’ = 6 – 1 = 5 units per day Share of ‘D’ = (5 / (5 + 1 + 3)) × 1800 = 5/9 × 1800 = Rs 1000
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x² - 8x + 15 = 0 ...
I. 6x² - 23x + 7 = 0
II. 6y² - 29y + 9 = 0
I. 5x² = 19x – 12
II. 5y² + 11y = 12
I. 2p2 - 3p – 2 = 0 II. 2q2 - 11q + 15 = 0
I: x2 - 33x + 242 = 0
II: y2 - 4y - 77 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 36x + 288 = 0
Equation 2: y² - 36y + 320 = 0
I. 5x2 – 18x + 16 = 0
II. 3y2 – 35y - 52 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 24x + 143 = 0
Equation 2: y² - 20y + 96 = 0
I. 35x² - 46x – 16 = 0
II. 35y² - 116y + 96 = 0
I. x2 – 3(x + 5) = -11
II. y2 – 4(y + 2) = -2y
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