Question
βDβ and βEβ can complete a project in 40 days,
while βEβ and βFβ can complete it in 60 days. βDβ and βEβ worked together on it for 30 days and then βFβ alone completed the remaining work in 20 days. If βDβ, βEβ, and βFβ started the project and worked together till its completion for which they received Rs. 1800 as total wage, then the share of βDβ out of the total wage will be:Solution
Let the total amount of work = 240 units (LCM of 40 and 60) Work done by βDβ and βEβ together in one day = 240 / 40 = 6 units Work done by βEβ and βFβ together in one day = 240 / 60 = 4 units Work done by βDβ and βEβ together in 30 days = 30 Γ 6 = 180 units Remaining work = 240 - 180 = 60 units Efficiency of βFβ = 60 / 20 = 3 units per day Efficiency of βEβ = 4 - 3 = 1 unit per day Efficiency of βDβ = 6 β 1 = 5 units per day Share of βDβ = (5 / (5 + 1 + 3)) Γ 1800 = 5/9 Γ 1800 = Rs 1000
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