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      Question

      I. 2x2 + 3x - 9 = 0 II. 3y2

      - y - 10 = 0 In each of the following questions, there are two equations. You have to solve both equations and mark the correct answer.
      A if x < y Correct Answer Incorrect Answer
      B if x β‰₯ y Correct Answer Incorrect Answer
      C if x > y Correct Answer Incorrect Answer
      D if x = y or relationship cannot be established. Correct Answer Incorrect Answer
      E if x ≀ y Correct Answer Incorrect Answer

      Solution

      I. 2x2Β + 3x - 9 = 0 => 2x2Β + 6x – 3x - 9 = 0 => 2x(x + 3) – 3(x + 3) = 0 => (x + 3) (2x - 3) = 0 => x = -3, 3/2 II. 3y2Β - y - 10 = 0 => 3y2Β - 6y + 5y – 10 = 0 => 3y(y - 2) + 5(y - 2) = 0 => (y - 2) (3y + 5) = 0 => y = 2, -5/3 Hence, the relationship cannot be established between x and y.

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