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    Question

    I. 3x2 - 14x + 15 = 0 II.

    15y2 - 34 y + 15 = 0 In the following questions two equations numbered I and II are given. You have to solve both the equations. Give answer if;
    A If x = y or relationship between x and y cannot be established. Correct Answer Incorrect Answer
    B if x > y Correct Answer Incorrect Answer
    C if x < y Correct Answer Incorrect Answer
    D if x тЙе y Correct Answer Incorrect Answer
    E if x тЙд y Correct Answer Incorrect Answer

    Solution

    I. 3x2 - 14x + 15 = 0 3x2 - 9x - 5x + 15 = 0 3x(x – 3) – 5(x – 3) = 0 (x – 3) (3x – 5) = 0 x = 3 , 5/3 II. 15y² - 34y + 15 = 0 15y² - 25y - 9y + 15 = 0 5y(3y – 5) – 3(3y – 5) = 0 (3y – 5) (5y – 3) y = 5/3 , 3/5 Hence, x ≥ y

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