Question
I. 6x² - 49x + 99 = 0 II. 5y² + 17y + 14 =
0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. 6x² - 49x + 99 = 0 6x² - 27x - 22x + 99 = 0 3x(2x – 9) - 11 (2x – 9) = 0 (3x – 11) (2x – 9) = 0 x = 11/3 , 9/2 II. 5y² + 17y + 14 = 0 5y² + 10y + 7y + 14 = 0 5y(y + 2) + 7(y + 2) = 0 (5y + 7) (y + 2) = 0 y = - 2, 7/5 Hence x > y.
A number n when divided by 6, leaves a remainder of 3. What will be the remainder when (n² +5n+8) is divided by 6?
How many divisors does the number 5040 have?
If '5731x7' is a six-digit number which is divisible by 33, then calculate the value of 'x'.
If a nine-digit number 785x3678y is divisible by 72, then the value of (x − y) is:
The largest 5 digit number which is exactly divisible by ‘33’ is:
Which of the following numbers is divisible by 11?
An eight-digit number, 73x216y4 is divisible by 72. Find the maximum possible value of x + y.
An eight-digit number, 81x3y72 is divisible by 72. Find the maximum possible value of x + y.
Which of the following pairs of non-zero values of p and q make 6-digit number 674pq0 divisible by both 3 and 11?
When a number is divided by 21, the quotient is 160, and the difference between the quotient and the remainder is 144. Find the number.