I. 5x² = 19x – 12
II. 5y² + 11y = 12
I. 5x² = 19x – 12 5x² - 19x + 12 = 0 5x² - 15x - 4x + 12 = 0 5x(2x – 3) - 4 (x – 3) = 0 (5x – 4) (x – 3) = 0 x = 3, 4/5 II. 5y² + 11y = 12 5y² + 11y – 12 = 0 5y² + 15y - 4y – 12 = 0 5y(y + 3) - 4(y + 3) = 0 (5y – 4) (y + 3) = 0 y = - 3, 4/5 Hence x ≥ y.
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