Question
The following question contains two equations as I and
II.You have to solve both equations and determine the relationship between them. I). 2a² - a – 78 = 0 II). b² + 26b + 168 = 0Solution
I. 2a² - a -78 = 0 2a² + 12a - 13a - 78 = 0  2a (a+6) -13 (a+6) = 0  (a+6) (2a-13) = 0  a = -6, 6.5 II. b²+26b+168 = 0 b² + 12b + 14b + 168 = 0 b (b+12) +14 (b+12) = 0 (b+12) (b+14) = 0 b = -12, -14 Therefore a > b.
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