Question
There are three envelopes with three different
addresses writen on them. Three leters are to be enclosed in these three envelopes such that one leter goes inside one envelope without seeing the address writen on any envelope. What is the probability that each of the three leters goes into the envelope with correct address writen on it?Solution
Total no. of ways =3!=6 and favourable no.of ways =1. So, required probability = 1/6
Statements: M % C & G @ T $ D; W % M # P
Conclusions : I. D % C II. M % G ...
Statements: G > N > P = E ≥ H < L; M < E < B < C = Q > X; U > W > Y = Q > H
Conclusions:
I). U > P
II). Y > P
...Statements: A > B; C > D; E ≥ A; F = C; C < B
Conclusions:
(i) B > D (ii) A > F (iii) F < E
...Which of the following symbols should replace the question mark in the given statement in order to make conclusion 'B>Z' as well as 'C>X' definitely tr...
Statements: F % W, W © R, R @ M, M $ D
Conclusions:
I.D @ R II.M $ F�...
Statements: H > S ≥ F = B ≤ U≤ T; E ≤ B ≤ K
Conclusions:I. K > F II. K = F
Statements: B > K < Y, E > C ≥ O = Y
Conclusions:
I. C > B
II. E ≤ Y
III. E > K
IV. O ≥ K
...Statements: B > D = C ≥ E ≥ G, C = H ≤ I < F
Conclusions:
I. B > H
II. I ≥ G
III. F > DStatement: E < F ≤ G = H, I ≥ G ≤ J ≤ K
Conclusion: I. K > E II. H > K
...Statement: W>Y<X<Z=U>S; W<T ≥V
I. Y<T
II. X > V
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