Get Started with ixamBee
Start learning 50% faster. Sign in now
Get Started with ixamBee
Start learning 50% faster. Sign in nowTotal no. of ways =3!=6 and favourable no.of ways =1. So, required probability = 1/6
(44/25) ÷ (154/199.5) × 419.91 = ? – (11.11)3
[34.01 × 18.98 – 12 × √576.03 – 198] ÷ 3.95 = ?
20.11% of 159.99 + √99.97 ÷ 5.02 = ?
41.98% of 2200.031 + 15% of 3999.9 = ?
9.992 + (6.01 × 7.98) + ? = 320.03
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
?% of (128.31 ÷ 15.97 × 75.011) = 419.98
37.5% of [34.99 ÷ (21.07/5.98) of 7.99 ÷ 2.18] = ?