Question
A person and his wife appear in the interview for the
two vacancies of a post. The probability of the selection of the husband and that of the wife are 1/7 and 1/5 respectively. What is the probability that only one of them will be selected?Solution
Probability of selection of husband = 1/7, it means of not selecting = 6/7 Probability of selection of wife = 1/5, it means of not selecting = 4/5 So, only 1 will be selected = “Wife selected, and husband is not selected” or “husband selected and wife doesn’t” = (1/5)* (6/7) + (1/7)* (4/5) = 6/35 + 4/35 = 10/35 = 2/7
More ESIC Part B Questions
Simplify the expression:
(9x² - 25) / (3x + 5)
√? × 4 - 374 + 127 + 300 = 117
Find the simplified value of the following expression:
14.25 × 32 – 11.4 × 15 + 8 – 712 ÷ 8 + 34.15 × 20 – 27 × 21 = ?
...- 55% of 220 – 15% of 40 = 20% of ?
(21 X 5) + ? = (480 - 120) ÷ 3
125 + 30% of 250 + √576 = ?
32 × 3 (54 – 15) + 186 ÷ 3 ÷ 2 – (21)² = ?
Find the simplified value of the given expression:
8 of 7 ÷ 2 × 5² + √36 – 10216% of 350 + 273 = ?2 × 21
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