Question
Suppose both the roots of q² + kq + 49 = 0 are real and
equal, then determine the value of 'k'.Solution
ATQ,
Suppose both the roots of equation ax² + bx + c = 0 are real and equal, then b²- 4ac = 0.
So, k²- 4 × 49 = 0
Or, k² = 196
Or, 'k' = ±14
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