I. 12a2– 55a + 63 = 0 12a2– 27a – 28a+ 63 = 0 3a (4a - 9) – 7 (4a - 9) = 0 (3a-7) (4a-9) = 0 a = 7/3, 9/4 II. 8b2 – 50b + 77 = 0 8b2 – 28b – 22b + 77 = 0 4b (2b – 7) – 11(2b – 7) = 0 (4b-11) (2b-7) = 0 b = 11/4, 7/2 Hence, a ˂ b
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