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    Question

    I.12a2– 55a + 63 = 0

    II. 8b2- 50b + 77 = 0
    A 1 Correct Answer Incorrect Answer
    B 2 Correct Answer Incorrect Answer
    C 3 Correct Answer Incorrect Answer
    D 4 Correct Answer Incorrect Answer
    E 5 Correct Answer Incorrect Answer

    Solution

    I. 12a2– 55a + 63 = 0 12a2– 27a – 28a+ 63 = 0 3a (4a - 9) – 7 (4a - 9) = 0 (3a-7) (4a-9) = 0 a = 7/3, 9/4 II. 8b2 – 50b + 77 = 0 8b2 – 28b – 22b + 77 = 0 4b (2b – 7) – 11(2b – 7) = 0 (4b-11) (2b-7) = 0 b = 11/4, 7/2 Hence, a ˂ b

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