Question
I. 8a2 – 22a+ 15 = 0 II.
12b2 - 47b + 40=0Solution
I. 8a2 – 22a + 15 = 0 8a2 – 10a - 12 + 15 = 0 2a(4a - 5) - 3(4a - 5)=0 (2a-3)(4a - 5)=0 a= 3/2 , 5/4 II. 12b2 - 47b+40=0 12b2 -32b -15y+40=0 4y(3b-8) - 5(3b-8)=0 (4b - 5)(3b-8)=0 b = 5/4 , 8/3 Hence, the relationship cannot be established
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