Question
In a cricket match the captain of one of a team scored
23 runs more than the average runs scored by the remaining 9 batsmen of that team who batted in the match. If the total runs scored by all the batsmen of that team were 223, how many runs did the captain score?Solution
Let the average runs scored by the remaining 9 batsmen be x. So, runs scored by the captain = x + 23 Total score of the team = 9x + x + 23 = 10x + 23Â => 10x + 23 = 223Â => x = 20 So, the score of the captain = 20 + 23 = 43
95.001% of 8219.99 - 4/9 % of 5399.98 + 109.99 = ?Â
25.05% of 220.05 – 10.15% of 119.99 × 2.02 = ?
16.98 × 88.05 + 1999.996% of 299.08 + 5.005 % of 4999.997 = ? × 20.98 × 40.009
(32.18% of 2399.89 - √624 × 26.25) % of 149.79 = ?
(752.09 - 43.04 x 7.94) ÷  16.9 = ?
(44/25) ÷ (154/199.5) × 419.91 = ? – (11.11)3
39.99% of 159.98 = ?2 – 319.99% of 12.5 – 49.98% of 129.99
15.22 × 9.99 + 150.15 = ?
Raju invests Rs. (p + 200) at a simple interest rate of 25% per annum for a period of 6 years and earns a total interest of Rs. (...
2660.03 ÷ 69.98 x 49.9 = ? + 10.32
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