I. 2b2 + 31b + 99 = 0 2b2 + 9b + 22b + 99 = 0 b (2b + 9) + 11(2b + 9) = 0 (b + 11) (2b + 9) = 0 b = -11, -9/2 II. 4a2 + 8a - 45 = 0 4a2 - 10a + 18a - 45 = 0 2a (2a - 5) + 9 (2a - 5) = 0 (2a + 9) (2a - 5) = 0 a = -9/2, 5/2 Hence, a ≥ b
(3500 ÷ √1225) × √(20.25) = ? ÷ 4
27% of 250 – 0.02% of 1000 is equal to:
(√529 + 63 /8)% of 800 = ?% of 250
The value of [(3√2+2) × (3√2-2)] of 13 + 15 is:
√4096 + √3249 = (?)2
5.5 × 3.2 × 2.3 = ?
15% of 695 – 12.5% of 250 =? – 1200
9 × 40× 242 × 182= ?2
40% are the passing marks. A student gets 250 marks yet fails by 38 marks. What is the maximum marks?