Question
I. 15b2 + 26b + 8 = 0 II. 20a2
+ 7a - 6 = 0Solution
I. 15b2 + 26b + 8 = 0 15b2 + 6b + 20b + 8 = 0 3b(5b+2) + 4(5b+2) = 0 (3b+4)(5b+2) = 0 b = -4/3 , -2/5 II. 20a2 + 7a - 6 = 0 20a2 + 15a - 8a - 6 = 0 5a(4a+3) - 2(4a+3) a = 2/5 , -3/4 Hence, relationship cannot be established
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