Question
Half-life of a radioactive substance is 10 days. The
time after which only 1/16th of it remains is:Solution
The substance reduces to 1/2 every 10 days. Time = n x Half-life Given: Half-life = 10 days Final amount = 1/16 of original
Thus, Time = n x Half-life = 4. 10 = 40 days
A sequence {Sₙ} is defined by:
Condition I: S₁ = 3 and for all n ≥ 2, Sₙ = 2·Sₙ₋₁ + (−1)ⁿ.
Condition II: The second ter...
27 44 63 86 ? 146
6 16 116 566 2272 6814
11 a�...
100, 110, ?, 171.6, 240.24, 360.36
31 16.5 18 �...
104 136 152 160 164 ?
...30 32 67 206 ? 4166
625, 5, 125, 25, 25, ? , 5
16 4 2 1.5 1 1.875
...130 155 146 195 186 ?
...