Question
Determine the value of [(sin7x - sin5x) ÷ (cos7x +
cos5x)] - [(cos6x - cos4x) ÷ (sin6x + sin4x)]?Solution
ATQ,
ATQ, [(sin 7x - sin 5x) ÷ (cos 7x + cos 5x)] - [(cos 6x - cos 4x) ÷ (sin 6x + sin 4x)] Applying the formulas, sinC + sinD = 2sin[(C + D) /2] cos[(C - D) /2] sinC - sinD = 2cos[(C + D) /2] sin[(C - D) /2] cosC + cosD = 2cos[(C + D) /2] cos[(C - D) /2] cosC - cosD = - 2sin[(C + D) /2] sin[(C - D) /2] ⇒ [(2cos6xsinx) ÷ (2 cos6xcosx)] - [(-2 sin5xsinx) ÷ (2sin5xcosx)] ⇒ tanx + tanx = 2tanx
290 × 15 ÷ 5 + 34 + 50 = ?Â
What is the value of ‘x’ if x% of 720 added to {2160 ÷ x of 20} × 2 gives 180?
13/3 – (23/6) = ? – (22/9)
The valueof2 of5– 1/2 −[4÷2– 1/3 −{3/4−(5– 1/2 – 3/4 )}]is :
182 – 517 ÷ 11 - √361 = ?
(65% of 120) = 25% of ? - 22
√3598 × √(230 ) ÷ √102= ?
What will come in the place of question mark (?) in the given expression?
√64 X 9 ÷ 3 + 12 X 3 = ? + 3635% of 840 + 162 = ? – 25% × 300
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