Question
I: x2Â + 31x + 228 = 0 II:
y2 + 3y – 108 = 0 Direction: In each of the following question, two equations are given. You have to solve both the equations to find the relation between x and y.Solution
x2 + 31x + 228 = 0 x2 + 19x + 12x + 228 = 0 x(x + 19) + 12(x + 19) = 0 (x + 12)(x + 19) = 0 x = -12, -19 y2 + 3y – 108 = 0 y2 + 12y – 9y – 108 = 0 y(y + 12) – 9(y + 12) = 0 (y – 9)(y + 12) = 0 y = 9, -12 x ≤ y
I. y/16 = 4/yÂ
II. x3 = (2 ÷ 50) × (2500 ÷ 50) × 42 × (192 ÷ 12)
I: x2Â + 31x + 228 = 0
II: y2 + 3y – 108 = 0
I. 5q = 7p + 21
II. 11q + 4p + 109 = 0
The roots of x² − (k+3)x + (3k − 1) = 0 are real and distinct, and the larger root exceeds the smaller by 5. Find k.
I. 64x2 - 64x + 15 Â = 0 Â Â Â Â
II. 21y2 - 13y + 2Â =0
- Suppose both the roots of q² + kq + 49 = 0 are real and equal, then determine the value of 'k'.
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 2x² - 8x + 6 = 0
Equation 2: y² - 7y + 10 = 0
I. 20x² - 93x + 108 = 0
II.72y² - 47y - 144 = 0
How many values of x and y satisfy the equation 2x + 4y = 8 & 3x + 6y = 10.
I. 12y2 + 11y – 15 = 0
II. 8x2 – 6x – 5 = 0
