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    Question

    I: 2x² - 8x + 6 = 0 II: 3y² - 12y + 9 =

    0 In each of the following question, two equations are given. You have to solve both the equations to find the relation between x and y.
    A x > y Correct Answer Incorrect Answer
    B x ≥ y Correct Answer Incorrect Answer
    C x < y Correct Answer Incorrect Answer
    D x ≤ y Correct Answer Incorrect Answer
    E x = y or no relation Correct Answer Incorrect Answer

    Solution

    From equation 1: 2x² - 8x + 6 = 0 Dividing by 2: x² - 4x + 3 = 0 Factorizing: (x - 3)(x - 1) = 0 So, x = 3 or x = 1. From equation 2: 3y² - 12y + 9 = 0 Dividing by 3: y² - 4y + 3 = 0 Factorizing: (y - 3)(y - 1) = 0 So, y = 3 or y = 1. Comparing x and y: • x = 3, y = 3, x = y • x = 3, y = 1, x > y • x = 1, y = 3, x < y • x = 1, y = 1, x = y

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