Question
I. 2x² - 11x + 12 = 0 II. 12y² + 29y +
15 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. 2x² - 11x + 12 = 0 2x² - 8x - 3 x + 12 = 0 2 x(x – 4) – 3(x – 4) = 0 (2 x – 3) (x – 4) = 0 ∴ x = 3/2, 4 II. 12y² + 29y + 15 = 0 12y² + 20y + 9 y + 15 = 0 4 y(3 y + 5) + 3(4 y + 5) = 0 (3 y + 5) (4 y + 3) = 0 ∴ y = -3/4, -5/3 Hence, x>y
- What will come in place of (?) in the given expression.
√324 + √121 – √49 = ? What will come in the place of question mark (?) in the given expression?
128 + 16 X 6 - ? = 88 + 4 X 26Â
290 × 15 ÷ 5 + 34 + 50 = ?Â
(3/7 )Of 3360 ÷ 240 + 30 = (?)²
23 × 20 + ? = 182 + 92 + 82
26% of 950 + 50/3% of 7962 = ? Â
6 0 - 20 [8 + 12 {8-8 (20-12)+20}-40] ÷ 16 =?
13 X √? + 256 ÷ 4 = 30% of 900 - 50
(13 X 11) + (19 X 3) = 400% of √?
√225 + 27 × 10 + ? = 320