Answer-I. 2y² - 3y – 14 = 0 II. 3x² - 7x + 4 = 0

I. 2y - 3y 14 0 2y - 7y 4 y 14 0 y 2 y 7 2 2 y 7 0 y 2 2 y 7 0 y -2, 72 II. 3x - 7x 4 0 3x - 4x - 3 x 4 0 x 3 x 4 1 3 x 4 0 x 1, 43 Hence, relationship cannot be established between x and y Alternate Method if signs of quadratic equation is - ve and -ve respectively then the roots of equation will be -ve and ve. note -ve sign will come in smaller root So, roots of first equation y -2, 72 if signs of quadratic equation is - ve and ve respectively then the roots of equation will be ve and ve. So, roots of second equation x 1, 43 After comparing we can conclude that relationship cannot be established.

Question

I. 2y² - 3y – 14 = 0 II. 3x² - 7x + 4 =

0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and find out the correct option. Give answer if ;

A if x > y

B if x ≥ y

C if x ≤ y

D if x = y or the relationship cannot be established

E if x < y

Practice Next