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    Question

    I. 6x² + 37x + 45 = 0 II. 3y² - 11y + 6 =

    0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and find out the correct option. Give answer if ;
    A if x > y Correct Answer Incorrect Answer
    B if x ≥ y Correct Answer Incorrect Answer
    C if x < y Correct Answer Incorrect Answer
    D if x ≤ y Correct Answer Incorrect Answer
    E if x = y or the relationship cannot be established Correct Answer Incorrect Answer

    Solution

    I. 6x² + 37x + 45 = 0 6x² + 10x  + 27x + 45 = 0 2 x (3 x + 5) + 9 (3 x + 5) = 0 (2 x + 9) (3 x + 5) = 0 ∴ x = -9/2, -5/3 II. 3y² - 11y + 6 = 0 3y² - 2y - 9 y + 6 = 0 y (3 y – 2) – 3(3 y – 2) = 0 (y – 3) (3 y – 2) = 0 ∴ y = 3, 2/3 Hence, x < y.

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