Question
I. 6x² + 37x + 45 = 0 II. 3y² - 11y + 6 =
0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and find out the correct option. Give answer if ;Solution
I. 6x² + 37x + 45 = 0 6x² + 10x  + 27x + 45 = 0 2 x (3 x + 5) + 9 (3 x + 5) = 0 (2 x + 9) (3 x + 5) = 0 ∴ x = -9/2, -5/3 II. 3y² - 11y + 6 = 0 3y² - 2y - 9 y + 6 = 0 y (3 y – 2) – 3(3 y – 2) = 0 (y – 3) (3 y – 2) = 0 ∴ y = 3, 2/3 Hence, x < y.
- 160, 340, 240, 480, 360, 720
256Â Â Â 768Â Â Â 96Â Â Â 288Â Â Â 35Â Â Â 108
384, 1152, 144, 432, 56, 162
5000, 4050, 3240, 2268, 1360.8, 680.4
- Find the wrong number in the given number series.
12, 21, 5, 38, 2, 71 191 341 221 331 251 281
- Find the wrong number in the given number series.
25, 34, 18, 34, 9, 46 12, 91, 172, 249, 328, 407
8 10.4 6.8 10.2 7.6 10
Find the wrong number in the given number series.
84, 120, 183, 246, 336, 444