Question
I. 63x² + 146x + 80 = 0 II. 42y² + 109y
+ 70 = 0Solution
I. 63x² + 146x + 80 = 0 63x² + 90x + 56x + 80 = 0 9x(7x + 10) + 8(7x + 10) = 0 (9x + 8) (7x + 10) = 0 ∴ x = (-8)/9, (-10)/7 II. 42y² + 109y + 70 = 0 42y² + 60y + 49y + 70 = 0 6y(7y + 10) + 7(7y + 10) = 0 (6y + 7) (7y + 10) = 0 ∴ y = (-7)/6, (-10)/7 Hence, relationship cannot be established between x and y
1784.04 - 483.98 + 464.98 ÷ 15.06 = ?3
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(168.24 ÷ 23.98) x 19.81 + ? = 176.33
64.889% of 399.879 + √? = 54.90% of 799.80 – 44.03% of 400.21
A bag contains 25 white and some black balls. If the probability of drawing a black ball from the bag is thrice that of drawing a white ball, fin...
49.96% of 120.21 + √(15) ÷ 1.87 × 4.41 = ?Â
619.97 ÷ 20.01 X 124.99 ÷ 24.91 = ?
180.25 × 14.995 ÷ √26 = ? × 5.985
A number is first increased by 35% and then decreased by 35%. If the net change in the number is 302.5, then find the original number.
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