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    Question

    I. 40x² + 81x + 35 = 0 II. 63y² + 103y + 42 =

    0
    A If x Correct Answer Incorrect Answer
    B If x>y Correct Answer Incorrect Answer
    C If x=y or no relationship cannot be established between x and y Correct Answer Incorrect Answer
    D If x≥y Correct Answer Incorrect Answer
    E If x≤y Correct Answer Incorrect Answer

    Solution

    I. 40x² + 81x + 35 = 0 40x² + 56x + 25x + 35 = 0 8x (5x + 7) + 5 (5x + 7) = 0 (8x + 5) (5x + 7) = 0 ∴ x = (-5)/8, (-7)/5 II. 63y² + 103y + 42 = 0 63y² + 49y + 54y + 42 = 0 7y (9y + 7) + 6 (9y + 7) = 0 (7y + 6) (9y + 7) = 0 ∴ y = (-6)/7, (-7)/9 Hence, relationship cannot be established between x and y.

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