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Question

I. 35x² + 83x + 36 = 0

II. 42y² + 53y + 15 = 0

A x < y Correct Answer Incorrect Answer
B x > y Correct Answer Incorrect Answer
C x = y or no relationship cannot be established between x and y. Correct Answer Incorrect Answer
D x ≥ y Correct Answer Incorrect Answer
E x ≤ y Correct Answer Incorrect Answer

Solution

I. 35x² + 83x + 36 = 0 35x² + 63x + 20x + 36 = 0 7x (5x + 9) + 4(5x + 9) = 0 (7x + 4) (5x + 9) = 0 x = - 4/7 , - 9/5 II. 42y² + 53y + 15 = 0 42y² + 18y + 35y + 15 = 0 6y(7y + 3) + 5(7y + 3) (6y + 5) (7y + 3) = 0 y = - 5/6 , - 3/7 Hence no relationship can be established.

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