Question
In the question, two equations I and II are given. You
have to solve both the equations to establish the correct relation between 'p' and 'q' and choose the correct option. I. 9p2 + 108p + 243 = 0 II. 12q2 - 108q + 216 = 0Solution
ATQ, I. 9p2 + 108p + 243 = 0 Pairs = 27, 81 And now dividing by a and by changing the sign we get, p = -3, -9 II. 12q2 - 108q + 216 = 0 Pairs = -36, -72 And now dividing by a and by changing the sign we get, q = 3, 6 ∴ p < q.
More Quadratic equation Questions
I. x2 – 10x + 21 = 0
II. y2 + 11y + 28 = 0
I. x2 + x – 42 = 0
II. y2 + 6y – 27 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 40x + 300 = 0
Equation 2: y² - 30y + 216 = 0
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
I. 10p² + 21p + 8 = 0
II. 5q² + 19q + 18 = 0
I). p2 = 81
II). q2 - 9q + 14 = 0
I. 15b2 + 26b + 8 = 0
II. 20a2 + 7a - 6 = 0
I. 15y2 + 4y – 4 = 0
II. 15x2 + x – 6 = 0
I. 3y² - 20y + 25 = 0
II. 3x² - 8x + 5 = 0
I. 5x2 – 18x + 16 = 0
II. 3y2 – 35y - 52 = 0
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