I. x2 – 18x + 81 = 0
II. y2 – 3y - 28 = 0

I. x² – 18x + 81 = 0 => x² – 9x – 9x + 81 = 0 => x (x – 9) – 9(x – 9) = 0 => x = 9, 9 II. y² – 3y - 28 = 0 => y² – 7y + 4y - 28 = 0 => y (y – 7) + 4 (y – 7) = 0 => y = 7, -4 Hence, x > y Alternate Method: if signs of quadratic equation is - ve and +ve respectively then the roots of equation will be +ve and +ve. So, roots of first equation = x = 9, 9 if signs of quadratic equation is - ve and -ve then the roots of equation will be +ve and -ve respectively. (note: +ve sign will come in larger value) So, roots of second equation = x = 7, -4 After comparing we can conclude that x > y.