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From I => x2 - 33x + 242 = 0 => x2 - 22x - 11x + 242 = 0 =>x(x – 22) -11(x – 22) = 0 => (x – 11) (x – 22) = 0 => x = 11, 22 From II => y2 - 4y - 77 = 0 => y2 – 11y + 7y - 77 = 0 =>y(y - 11) +7(y – 11) = 0 => (y + 7) (y – 11) = 0 => y = -7, 11 Hence, x ≥ y
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