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    Question

    I. (y тАУ 5)2 тАУ 9 = 0 II.

    x2 тАУ 3x + 2 = 0 In each of these questions, two equation I and II are given. You have to solve both the equations and give answer:
    A if x > y Correct Answer Incorrect Answer
    B if x < y Correct Answer Incorrect Answer
    C if x тЙе y Correct Answer Incorrect Answer
    D if x тЙд y Correct Answer Incorrect Answer
    E if x = y or no relation can be established between x and y. Correct Answer Incorrect Answer

    Solution

    I. (y тАУ 5)2┬атАУ 9 = 0 y2┬а+ 25 тАУ 10y - 9 = 0 y2┬атАУ 10y + 16 = 0 y2┬атАУ 8y - 2y + 16 = 0 y(y тАУ 8) тАУ 2(y тАУ 8) = 0 (y тАУ 8) (y тАУ 2) = 0 y = 8, 2 II. x2┬атАУ 3x + 2 = 0 x2┬атАУ 2x тАУ x + 2 = 0 x(x - 2) тАУ 1(x - 2) = 0 (x - 2) (x тАУ 1) = 0 x = 2, 1 Hence, x┬атЙд┬аy

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