Question
I. (y β 5)2 β 9 = 0 II.
x2 β 3x + 2 = 0 In each of these questions, two equation I and II are given. You have to solve both the equations and give answer:Solution
I. (y β 5)2Β β 9 = 0 y2Β + 25 β 10y - 9 = 0 y2Β β 10y + 16 = 0 y2Β β 8y - 2y + 16 = 0 y(y β 8) β 2(y β 8) = 0 (y β 8) (y β 2) = 0 y = 8, 2 II. x2Β β 3x + 2 = 0 x2Β β 2x β x + 2 = 0 x(x - 2) β 1(x - 2) = 0 (x - 2) (x β 1) = 0 x = 2, 1 Hence, xΒ β€Β y
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