Question
I. (y – 5)2 – 9 = 0 II.
x2 – 3x + 2 = 0 In each of these questions, two equation I and II are given. You have to solve both the equations and give answer:Solution
I. (y – 5)2 – 9 = 0 y2 + 25 – 10y - 9 = 0 y2 – 10y + 16 = 0 y2 – 8y - 2y + 16 = 0 y(y – 8) – 2(y – 8) = 0 (y – 8) (y – 2) = 0 y = 8, 2 II. x2 – 3x + 2 = 0 x2 – 2x – x + 2 = 0 x(x - 2) – 1(x - 2) = 0 (x - 2) (x – 1) = 0 x = 2, 1 Hence, x ≤ y
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