Question
I. 6x2 – 7x - 20 = 0 II.
3y2Â - y - 14 = 0 In each of these questions, two equation I and II are given. You have to solve both the equations and give answer:Solution
I. 6x2 – 7x - 20 = 0 6x2 – 15x + 8x - 20 = 0 3x(2x - 5) + 4(2x - 5) = 0 (2x - 5) (3x + 4) = 0 x = 5/2, -4/3 II. 3y2 - y - 14 = 0 3y2 – 7y + 6y - 14 = 0 y(3y – 7) + 2(3y – 7) = 0 (y + 2) (3y – 7) = 0 y = -2, 7/3 Hence, the relationship cannot be established between x and y.
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