Question
Solve the quadratic equations and determine the relation
between x and y: Equation 1: x² - 22x + 120 = 0 Equation 2: y² - 25y + 144 = 0Solution
From Equation 1: x² - 22x + 120 = 0 Factorizing: (x - 10)(x - 12) = 0 So, x = 10 or x = 12. From Equation 2: y² - 25y + 144 = 0 Factorizing: (y - 9)(y - 16) = 0 So, y = 9 or y = 16. Comparing x and y: x = 10, y = 9 → x > y x = 10, y = 16 → x < y x = 12, y = 9 → x > y x = 12, y = 16 → x < y
I: √(100 x4 + 125x4) + 7x + 41/2 = -4x
II: 3√(64y3) x 2y + 19y + 72 = -3y +...
I. 5x² - 28x + 39 = 0
II. 2y² - 13y + 20 = 0
I. 3p² - 14p + 15 = 0
II. 15q² - 34q + 15 = 0
I. 12x2 - 55x + 63 = 0
II. 10y2 - 47y + 55 = 0
I. 7x + 8y = 36
II. 3x + 4y = 14
I. 2x2 – 5x – 63 = 0
II. 2y2 – 7y – 72 = 0
I). 5p2 Â - p - 4 = 0
II). q2 - 12q + 27 = 0
I. 15b2 + 26b + 8 = 0
II. 20a2 + 7a - 6 = 0
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
l). p² - 26p + 153 = 0
ll). q² - 17q + 72 = 0
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