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    Question

    I: x² - 10x + 21 = 0   II: 4y² - 16y + 15 =

    0 In each of the following question, two equations are given. You have to solve both the equations to find the relation between x and y.
    A x > y Correct Answer Incorrect Answer
    B x ≥ y Correct Answer Incorrect Answer
    C x < y Correct Answer Incorrect Answer
    D x ≤ y Correct Answer Incorrect Answer
    E x = y or no relation Correct Answer Incorrect Answer

    Solution

    From equation 1: x² - 10x + 21 = 0 Factorizing: (x - 7)(x - 3) = 0 So, x = 7 or x = 3. From equation 2: 4y² - 16y + 15 = 0 Dividing by 4: y² - 4y + 3.75 = 0 Using the quadratic formula: y = [4 ± √(16 - 15)] / 2 y = [4 ± 1] / 2 So, y = 2.5 or y = 1.5. Comparing x and y: • x = 7, y = 2.5, x > y • x = 7, y = 1.5, x > y • x = 3, y = 2.5, x > y • x = 3, y = 1.5, x > y

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