Question
The sum of the monthly incomes of βAβ, βBβ and
βCβ is Rs. 40000 which is 4 times the monthly income of βCβ. If βAβ spends 30% of his income while βBβ spends 80% of his income and the sum of their savings is Rs. 18000, then find the savings of βAβ.Solution
Monthly income of βCβ = 40000/4 = Rs. 10000 Let the monthly income of βAβ be Rs. x Therefore, monthly income of βBβ = Rs. (30000 β x) According to the question, 0.70x + 0.20(30000 β x) = 18000 Or, 0.5x = 12000 x = 24000 Or, savings of βAβ = 0.7x = Rs. 16800
3/7 of 686 + 133(1/3)% of 33 β 69 =?
What will come in place of the question mark (?) in the following questions?
3/7 of 504 ÷ 12 + 17 = √?
134% of 1250 β 46% of 2120 = 4 Γ ?
24% of 15% of 500 + 122 = ?2 β (232 Γ· 2)
- What will come in place of (?), in the given expression.
(4Β² + 6Β²) Γ 2 = ? 5121.3Β Γ 641.8Β Γ· 80.5Β = 8?
β2025 + β1024 - β1296 = 20% of ?
52% of 400 + √(?) = 60% of 600 - 25% of 400
[(82 × 162)/12] - 28 = ?