Question
The sum of the monthly incomes of ‘A’, ‘B’ and
‘C’ is Rs. 40000 which is 4 times the monthly income of ‘C’. If ‘A’ spends 30% of his income while ‘B’ spends 80% of his income and the sum of their savings is Rs. 18000, then find the savings of ‘A’.Solution
Monthly income of ‘C’ = 40000/4 = Rs. 10000 Let the monthly income of ‘A’ be Rs. x Therefore, monthly income of ‘B’ = Rs. (30000 – x) According to the question, 0.70x + 0.20(30000 – x) = 18000 Or, 0.5x = 12000 x = 24000 Or, savings of ‘A’ = 0.7x = Rs. 16800
I. 20y² - 13y + 2 = 0
II. 6x² - 25x + 14 = 0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer Â
I. x2 – ...
I. 27x² + 120x + 77 = 0
II. 56y² + 117y + 36 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 50x + 600 = 0
Equation 2: y² - 51y + 630 = 0
l). p² - 29p + 204 = 0
ll). q² + 4q - 221 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 11x² - 93x + 88 = 0
Equation 2: 13y² + 118y + 93 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. x2 – 9x + 18 = 0
II. y2 – 5y + 6 = 0
Equation 1: x² - 90x + 2025 = 0
Equation 2: y² - 88y + 1936 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
Relevant for Exams:
