Question
The sum of the monthly incomes of βAβ, βBβ and
βCβ is Rs. 90000 which is 4 times the monthly income of βCβ. If βAβ spends 55% of his income while βBβ spends 80% of his income and the sum of their savings is Rs. 19000, then find the savings of βAβ.Solution
Monthly income of βCβ = 90000/4 = Rs. 22500 Let the monthly income of βAβ be Rs. x Therefore, monthly income of βBβ = Rs. (67500 β x) According to the question, 0.45x + 0.20(67500 β x) = 19000 Or, 0.25x = 5500 x = 22000 Or, savings of βAβ = 0.45x = Rs. 9900
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