Question
The sum of the monthly incomes of ‘A’, ‘B’ and
‘C’ is Rs. 55000 which is 4 times the monthly income of ‘C’. If ‘A’ spends 60% of his income while ‘B’ spends 80% of his income and the sum of their savings is Rs. 15500, then find the savings of ‘A’.Solution
Monthly income of ‘C’ = 55000/4 = Rs. 13750 Let the monthly income of ‘A’ be Rs. x Therefore, monthly income of ‘B’ = Rs. (41250 – x) According to the question, 0.4x + 0.20(41250 – x) = 15500 Or, 0.2x = 7250 x = 36250 Or, savings of ‘A’ = 0.40x = Rs. 14500
I. x2 - 20x + 96 = 0
II. y2 - 23y + 22 = 0
If 4x = 40, 3y = 33, what is the value of 6x + 4y?
I. 5x² = 19x – 12
II. 5y² + 11y = 12
I. 63x2 + 148x + 77 = 0
II. 21y2 + 89y + 88 = 0
I. x2 - 5x - 14 = 0
II. y2 - 16y + 64 = 0
I. x2 + 11x + 30 = 0
II. y2 + 17y + 72 = 0
I. 2x2 + 12x + 18 = 0
II. 3y2 + 13y + 12 = 0
l). 2p² + 12p + 18 = 0
ll). 3q² + 13q + 12 = 0
Quantity I: The price of rice is decreased by 30%, by how much % the consumption is increase so that the expenditure will decreased by 10%?
Quant...
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
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