Question
In an election contested between
two candidates, 75% of the total voters in the city participated in voting, out of which 20% of the votes were deemed invalid. The winning candidate secured 80% of the valid votes and defeated the opponent by a margin of 5112 votes. Determine the total number of voters in the city.Solution
ATQ, Let number of voters in the city be '100x' So, number of votes cast = 100x X 0.75 = '75x' Number of valid votes = 75x X 0.8 = '60x' Number of votes received by winner = 60x X 0.8 = '48x' Number votes received by loser = 60x - 48x = '12x' ATQ; 48x - 12x = 5112 So, 36x = 5112 So, x = 142 So, number of voters in the city = 142 X 100 = 14,200
62 + 43 + 625(1/4) - ? = 102
23% of 8040+ 42% of 545 = ?%of 3000
3.2% of 500 × 2.4% of ? = 288
What will come in the place of question mark (?) in the given expression?
(5/8) × 1600 + (2400 ÷ 25) = ?
√49 + √144% of 3600 = ?
62.94% of 1800 - 15.03 % of 2400 = ?
350% of (450 / 1.5) = ?% of 4200
1885 ÷ 64.98 + 7.29 + ? = 69.09