📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!
  • google app store apple app store
    • ✖

      Question

      Solve the quadratic equations and determine the relation

      between x and y: Equation 1: x² - 50x + 600 = 0 Equation 2: y² - 51y + 630 = 0
      A x > y Correct Answer Incorrect Answer
      B x ≥ y Correct Answer Incorrect Answer
      C x < y Correct Answer Incorrect Answer
      D x ≤ y Correct Answer Incorrect Answer
      E x = y or no relation Correct Answer Incorrect Answer

      Solution

      From Equation 1: x² - 50x + 600 = 0 Factorizing: (x - 20)(x - 30) = 0 So, x = 20 or x = 30. From Equation 2: y² - 51y + 630 = 0 Factorizing: (y - 21)(y - 30) = 0 So, y = 21 or y = 30. Comparing x and y: x = 20, y = 21, x < y x = 20, y = 30, x < y x = 30, y = 21, x > y x = 30, y = 30, x = y

      Practice Next
      More Quadratic equation Questions

      Relevant for Exams:

      ask-question