Question
A contractor assigned 18 laborers to complete a task in 16
days. Unfortunately, 6 laborers left after 6 days. How many additional days will be required to finish the work?Solution
ATQ,
Let each laborer's efficiency be 'e' units/day
Total work = 18 Γ 16 Γ e = 288e units
Work done in 6 days = 18 Γ 6 Γ e = 108e units
Remaining work = 288e - 108e = 180e units
Laborers left = 18 - 6 = 12
Time required = 180e Γ· (12 Γ e) = 15 days
Extra days = 15 - 10 = 5 days
- Find the simplified value of the given expression.
Find the simplified value of the given expression
((9.77)0- γ(0.1)γ(-1))/(γ(6/24 )γ(-1)Β Γ(3/2)3+ γ((-2)/6)γ(-1) ) = ?
...1111.25 × 9.05 + 2323.23 × 9.05 – 2121.37 ×9.05 =?
15.50% of 6240 β 426.31 = ?Β
8 Γ 25% of ? = 400
Simplify the following expressions and choose the correct option.
45% of 640 + (2/5 of 350) = ?
What will come in the place of question mark (?) in the given expression?
(20% of 820 β 56 + 11 Γ 8) 1/2 = ? β 62
24% of 400 × 16% of ? = 384
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