Question
A contractor assigned 18 laborers to complete a task in 16
days. Unfortunately, 6 laborers left after 6 days. How many additional days will be required to finish the work?Solution
ATQ,
Let each laborer's efficiency be 'e' units/day
Total work = 18 × 16 × e = 288e units
Work done in 6 days = 18 × 6 × e = 108e units
Remaining work = 288e - 108e = 180e units
Laborers left = 18 - 6 = 12
Time required = 180e ÷ (12 × e) = 15 days
Extra days = 15 - 10 = 5 days
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