Question
A, B, and C each have different rates of completing a
task; A can finish it in 36 days, B in 60 days, and C in 30 days. Initially, they begin the work collaboratively, but C departs after 5 days. Furthermore, A exits the job 18 days before the final completion. How long does it take to complete the entire task?Solution
Let the total work = 180 units (LCM of 36, 60 and 30) Amount of work done by A alone in one day = 180/36 = 5 units Amount of work done by B alone in one day = 180/60 = 3 units Amount of work done by C alone in one day = 180/30 = 6 units Amount of work done by A, B and C together in 5 days = 5 × (5 + 3 + 6) = 70 units Amount of work done by B alone in 18 days = 18 × 3 = 54 units Remaining work = 180 – 70 – 54 = 56 units Time taken by A and B together to complete 56 units work = 56/(5 + 3) = 7 days So the total time taken to complete the work = 5 + 18 + 7 = 30 days
(15 x 6 + 60% of 500 - 16 x 7) = ?
What will come in the place of question mark (?) in the given expression?
? = 70% of 36% of (25 × 320) + 150
? = 6.25% of 240 + 252 + 172 – 16 × 17
√1444 + √729 – √2116 = ?
96% of 4500 – 34% of 650 = ?
What will come in the place of question mark (?) in the given expression?
[{(24) 2 ÷ (6) 2 } ÷ 8]4 = ? ÷ 5
What value should come in the place of (?) in the following questions?
30% of 160 – 25% of 240 + 43 = ?
72 + 122 - 25% of 600 = ?
187 ÷ 5 ÷ 0.4 = ? – 24 × 2.4
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