Question
A man can complete a task in 20 days, a woman can finish
it in 30 days, and a boy can do the same task in 60 days. To complete the task in just 3 days, how many additional men are needed if the team already includes four boys and two women?Solution
Let the total work be 60 units. {LCM 20, 30 and 60} So, efficiency of each man = (60/20) = 3 units/day And efficiency of each woman = (60/30) = 2 units/day And efficiency of each child = (60/60) = 1 unit/day Work to be done on each day = 60 ÷ 3 = 20 units Let number of men required to finish the work in 3 days be 'x'. So, (3 X x) + (2 X 2) + (4 X 1) = 20 Or, 3x + 4 + 4 = 20 Or, 3x = 12 So, x = 4 So, 4 men should join to finish the work in 3 days.
15% of 1800 + 22 = ?
What will come in the place of question mark (?) in the given expression?
30% of 520 + 16% of 1500 = ? + 244
- What will come in place of the question mark (?) in the following questions?
(2⁴ + 6²) ÷ 2 = ? 4/5 + 6/7 × 14/42 ÷ 24/35 = ?
What will come in the place of question mark (?) in the given expression?
45% of (√6400 × 5) = ? + 111
If 1.123 × 3.211 = 3.122 + ______________, then the number in blank space is
Simplify and express as a fraction in simplest form:
0.75 + 0.4 − 0.125
- What will come in the place of question mark (?) in the given expression?
389 + 641 - ? = 180 X 2 15.8% of 9000 + 20.4% of 7500 = 30% of ?
2.4 of 7.2 of 1/57.6 of 4200 = ?
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